7s3

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783 Macartney 72 Cornwall 215 M'Dowall 21J Cornwallis 72 7M Cunningham 932 M'Kenzie 7S3 Widdrington 93 1 He Lancey 288 M'Ritchie 932 nt^wiaf Wigmore 71 Douglas 72. 432 Mahmsbury 304 Doyley 9S2 Meek 432 SE&UESTRA  7S3'2I11 7S3'2I11 LANO EIIE 3023 3023 3023 3023 3023 3023 3023 3023. LIST 'SISI SSSST О ССЦТАСТ ISSN АСС! АСС! ISSN ISSN АСС! АСС! ISSN ISSN PNSPSNTV ISSKSSS INSTITUTISN LT 21 SLK 1 WISTSSTE WYLIS. Т! 7SSSS  10 711973 () 782 10 712073 9 782 10 712173 5 782 0 10 7122 n i 782 0 10 712373 8 782 0 10 712473 4 "S2 0 10 712573 0 782 0 10 712673 7 7S2 0 10 712773 3 782 0 10 712873 X 7S2 10 74721 1 2 780 0 747301 1 "S3 0 747302 \ 7S3  5/2,7/2,9/2 45469.87

5/2,7/2,”/2.47289a 5/2,7/2,9/2 45471.70 4f7(*S*)6s (7S344p 5/2,7/2,9/2 || 47337.15 5/2,7/2,9/2 45481.97 4f7(*S*)6s (7S345p 5/2,7/2,9/2 || 47340.29 5/2,7/2,9/2 45490.70 4f7(*S*)6s (7S346p 5/2,7/2,”/2 || 47343.21 5/2 12.1.1: Z2(s) = k 0s + Z3 (s) where k0 = sZ2(s)|s=0 = 2 ⇒ Z3 (s) = Z2(s) − 2 s = 6s6 + 7s5 +46s4 + 38s3 + 79s2 + 25s + 36 (s2 +4)(s4 + 7s3 + 8s2 + 10s + 1) The s = 0 pole removal from an impedance function corresponds to a capacitor C1 CLUTCH, FRICTION EA 1 783 16 PADII 311001_0g33260 60380 RCB081214PS BEARING ROLLER NEED EA 1 7S3 17 PBDII 1680012017835 82402 42277D317 . NUB.BRAKEASSENBLY EA 1 788 1E PADII 5315006875218 96906 De Foreest. John Abeel, 783. John [., 783. Lawrence V., 783. Margaret, 783.

Maria..7S3. Peter, 783. Sarah. 783. Theodore Romalne (M. D.), 783. de Forest, Gerrlt, 692. Henricus, 370. John, 371. Maria, 701. Philip. 351. Rachel, 783. De Forest.7s3+1o". s. As the third quotient is negative, the given polynomial is not Hurwitz. There is no need to complete continued fraction expansion. b) All the coefficients are positive and all powers of s are present. n(s) = s3+2 s m(s) = 4s2+8 4s2 +8) S. Salivahanan & S. Pravin Kumar. Hence, due to even multiplicity, it is clear that A0(x) satisfies the condition A(w2) ≥ 0 for all w ≥ 0 where x = w2. Example 3.20 Check whether the following polynomials are Hurwitz or not. (i) A(s) = s4 + 7s3 + O BSERVATIONS— Continued. с У, Do July 21 783 783 783 7 s:;

783.783 788 7 S 3 7 s;! 783 783 783 783 783 788 783 783 7s:¡ 7s:í 7RS □ 83 783 7 s:; 783 783 7s:¡ 788 783 783 7s:¡ 7R3 7 S3 783 7s;¡ 783 783 7S3 783 7 S3 7S3 7 S3 7s 3